k-Means and Other Cost Minimization Clusterings
The objective function and the iterative algorithm are related but not identical ideas.
Two Meanings of k-Means
The phrase k-means clustering can refer to two related but different ideas. One idea is an objective function: a way to assign a cost to a proposed clustering. The other is an iterative procedure commonly used in practice to produce a clustering. Keeping these ideas separate prevents a common mistake: assuming that the procedure is guaranteed to find the clustering with the best possible objective value.
From Assignments to Cost
A k-means clustering assigns data points to clusters and gives each cluster a mean, also called its centroid. The objective function evaluates that arrangement by adding the squared Euclidean distances from the data points to the centroids of their assigned clusters. A smaller total means that the assigned points are, in aggregate, closer to their centroids according to this measure.
The objective function is useful because it turns a qualitative goal, keeping points close to the centers of their clusters, into one quantity that can be compared across proposed clusterings.
Distance and Assignment
Euclidean distance supplies the notion of closeness in this k-means formulation. For a data point, the relevant distance is the distance to the centroid of the cluster to which the point is assigned. That distance is then squared before it contributes to the objective's total cost. Thus, Euclidean distance plays two connected roles: it helps determine which centroid is closest during the iterative procedure, and it supplies the distances whose squared values are accumulated by the objective.
Finding a Cluster Mean
Once a cluster has been specified, its mean is computed component by component. For each coordinate, add the values from all vectors in the cluster and divide by the number of vectors. The resulting vector is not just a descriptive label: it is the value that minimizes the cluster's sum of squared Euclidean distances.
A three-vector cluster
Find the mean of the vectors (1, 1), (3, 1), and (2, 4).
First coordinate: Average the first coordinates: (1 + 3 + 2) divided by 3 gives 2.
Second coordinate: Average the second coordinates: (1 + 1 + 4) divided by 3 gives 2.
Assemble the vector: Place the coordinate averages in their original order.
The cluster mean is (2, 2).
Do not average whole vectors as indivisible objects. Match corresponding coordinates, average each coordinate separately, and then assemble the resulting coordinates into the mean vector.
The Iterative Procedure
In the commonly used iterative approach, points are reassigned to the nearest centroid, and the centroids are recomputed from the resulting clusters. These two operations form a repeating cycle. Reassignment changes which points belong to each cluster; recomputation changes the location of each cluster mean based on its current members. The procedure therefore produces a clustering through repeated state changes rather than by directly solving every possible clustering arrangement.
What do you think happens?
Suppose the current cluster membership changes after points are reassigned. What should happen to that cluster's centroid?
Reveal answer
Answer: It is recomputed as the component-by-component mean of the cluster's current vectors.
The iterative procedure recomputes centroids from the current cluster memberships, and the mean is the point that minimizes the cluster's sum of squared distances.
Optimal Versus Obtained
| Idea | Meaning | Key caution |
|---|---|---|
| Optimal k-means solution | A clustering that achieves the best possible value of the k-means objective | Finding this solution is computationally difficult. |
| Iterative algorithm outcome | The clustering produced by repeatedly assigning points and recomputing means | It is a practical procedure and is not guaranteed here to be the exact optimizer. |
It is natural to interpret k-means clustering as the clustering with the best possible objective value, but that interpretation is too strong. The optimization problem is NP-hard, and it is also NP-hard to approximate within some constant. In practice, a simpler iterative algorithm is often used instead. Its result can be locally optimal even when another clustering has a lower overall cost.
Common Reasoning Errors
Treating the iterative algorithm as a guaranteed exact optimizer
The optimization problem is computationally difficult, and the practical iterative procedure is not guaranteed here to find the exact optimum.
Fix:
Describe the result as the outcome of the iterative procedure unless optimality has been established separately.Using an arbitrary notion of closeness
Euclidean distance supplies the notion of closeness in this formulation.
Fix:
Use Euclidean distance when describing assignments and the corresponding squared distance when describing objective cost.Computing a vector mean without matching coordinates
A cluster mean is found by averaging vectors component by component.
Fix:
Average all first coordinates together, all second coordinates together, and continue this way for every coordinate.Confusing an evaluation quantity with an algorithm
The objective function evaluates a proposed clustering; reassignment and centroid recomputation describe the iterative procedure.
Fix:
Use objective function for the cost definition and iterative algorithm for the process that produces a clustering.
Practice the Separation
A proposed clustering assigns every vector to a centroid and has a total cost formed by summing squared Euclidean distances. Explain which part of the description is the objective function and which part would belong to the iterative algorithm. Then find the mean of the vectors (2, 0), (4, 2), and (0, 4) by averaging each coordinate separately.
Hints
- The objective function evaluates a completed assignment; it does not describe the sequence of reassignment and recomputation steps.
- For the mean, average the first coordinates together and then average the second coordinates together.
Checking the practice result
Find the mean of (2, 0), (4, 2), and (0, 4).
First coordinate: Average 2, 4, and 0 to obtain 2.
Second coordinate: Average 0, 2, and 4 to obtain 2.
The mean is (2, 2). The objective evaluates assignments using squared Euclidean distances, while the iterative algorithm repeatedly changes assignments and recomputes means.
Key Takeaways
- The k-means objective evaluates a clustering by summing squared Euclidean distances from points to their assigned centroids.
- Euclidean distance defines closeness for assignments, while its squared values contribute to the total cost.
- A cluster mean is computed component by component and minimizes the cluster's sum of squared distances.
- The commonly used iterative algorithm is a practical procedure, not the same thing as the globally optimal solution.
- A locally optimal iterative result can have a higher cost than another possible clustering.
Key Takeaways
- The objective function gives one cost for a proposed clustering.
- Euclidean distance determines closeness, and squared distances are accumulated in the cost.
- Cluster means are calculated by averaging corresponding vector coordinates.
- The iterative algorithm alternates between nearest-centroid assignments and recomputed means.
- The iterative result should not automatically be treated as the globally optimal k-means solution.