Concepts / Complex Numbers: Real and Imaginary Parts

Complex Numbers: Real and Imaginary Parts

Complex numbers support the usual arithmetic operations, so they can be added, subtracted, multiplied, and divided.

  • Programming

Can Complex Numbers Be Used Like Ordinary Numbers?

Once you meet complex numbers, a natural question follows: are they just a special notation, or can you actually compute with them the way you compute with everyday numbers? The short answer is that complex numbers are full participants in arithmetic. The usual arithmetic operations are supported for them, and the most common mathematical functions are supported too. This article explains what that support means in practice, how each operation is carried out, and where learners usually go wrong.

What do you think happens?

Before reading on, try to predict the result of (2+3i)(1-5i). Which of these do you think it is?

  • 2 - 15i

  • 17 - 7i

  • -13 + 13i

  • 17 + 13i

Reveal answer
Answer:

17 - 7i

Expanding gives 2 - 10i + 3i - 15i^2. Because i2 = -1, the last term becomes +15, so the total is 17 - 7i. Options that skip the i2 step or drop terms are the typical wrong answers, and the rest of this article shows how to avoid them.

Real and Imaginary Parts of a Complex Number

Definition

Every complex number has the form a + bi. The number a is the real part, the number b is the imaginary part, and i is the imaginary unit with the property i2 = -1.

The two-part structure is the key to everything that follows. A complex number is not treated as a single opaque quantity. Instead, its real part and its imaginary part are kept distinct, and each operation is carried out by working with those parts. Real parts are combined with real parts, and imaginary parts are combined with imaginary parts. Keeping this two-part view in mind makes every operation in this article easier to follow.

Because the form a + bi includes ordinary numbers as a special case, the usual operations can be extended to the full set of complex numbers. A number whose imaginary part is zero is simply a real number written in complex form, so the extension does not discard anything familiar. The source states that complex numbers support the usual arithmetic operations, which is the reason they can be added, subtracted, multiplied, and divided.

Adding and Subtracting by Parts

Addition and subtraction are the most direct operations. For two complex numbers a + bi and c + di, you combine the real parts together and the imaginary parts together. The sum is found by adding the real parts and adding the imaginary parts, giving a single complex number in the same form.

Formula

Subtraction works the same way, with the second number's parts subtracted from the first. No product of imaginary units appears in either operation, so the calculation stays at the level of ordinary subtraction applied to each part.

Formula
Worked example

Subtracting two complex numbers

Compute (5+2i) - (3+7i).

  1. 1
    Identify the parts

    For the first number, a = 5 and b = 2. For the second number, c = 3 and d = 7.

  2. 2
    Subtract the real parts

    a - c = 5 - 3 = 2.

  3. 3
    Subtract the imaginary parts

    b - d = 2 - 7 = -5.

  4. 4
    Assemble the result

    Combine the two parts into the form real + imaginary i.

Result

2 - 5i

Multiplying With i Squared

Multiplication cannot be done one part at a time, because each part of the first number interacts with each part of the second. The method is to expand the product fully, as you would with brackets in algebra, and then replace i2 with -1. The standard result has a real part and an imaginary part.

Formula
(a+bi)(c+di)two complex numbersExpand every termeach part meets each partac, ad i, bc i, bdi^2 four collected termsReplace i^2 with -1the term bd i^2 changessign(ac - bd) + (ad +bc)ireal part and imaginarypartdistributecollectapply i^2 = -1combine parts
The steps that turn (a+bi)(c+di) into a single real part and imaginary part, showing where i2 is replaced by -1.
Worked example

Multiplying two complex numbers

Compute (2+3i)(1-5i).

  1. 1
    Expand the product

    2 times 1 gives 2, 2 times -5i gives -10i, 3i times 1 gives 3i, and 3i times -5i gives -15i^2.

  2. 2
    Collect the imaginary terms

    -10i + 3i = -7i.

  3. 3
    Replace i2 with -1

    -15i^2 = -15(-1) = 15. This is the sign-changing step.

  4. 4
    Combine the real parts

    2 + 15 = 17, so the real part is 17 and the imaginary part is -7.

Result

17 - 7i

Dividing Using the Conjugate

Division is handled by multiplying the top and bottom by the conjugate of the denominator. For a denominator c + di, the conjugate is c - di. This removes the imaginary unit from the denominator, leaving a real number there, so the result can be read off as a single real part and imaginary part.

Rule

The denominator simplifies because multiplying c + di by c - di produces c2 + d2 after the i2 = -1 replacement. The imaginary terms cancel in the denominator, which is why the result has no imaginary unit there. The numerator is then expanded in the same way as any product.

(a+bi) / (c+di)imaginary denominatorMultiply top andbottom by c-dithe conjugate of thedenominatorDenominator becomesc^2 + d^2 a real numberReal part over c^2 +d^2 , imaginary partover c^2 + d^2 single a+bi formExpand numerator,apply i^2 = -1still a complex valuemultiplydenominatornumeratordivide throughdivide through
The sequence of steps that removes the imaginary unit from the denominator and leaves a single real part and imaginary part.
Worked example

Dividing by a complex number

Compute (2+3i) / (1-5i).

  1. 1
    Find the conjugate

    The denominator is 1 - 5i, so its conjugate is 1 + 5i.

  2. 2
    Multiply top and bottom

    The numerator becomes (2+3i)(1+5i) and the denominator becomes (1-5i)(1+5i).

  3. 3
    Simplify the denominator

    (1-5i)(1+5i) = 1 + 5i - 5i - 25i^2 = 1 + 25 = 26. The imaginary unit has left the denominator.

  4. 4
    Expand the numerator

    (2+3i)(1+5i) = 2 + 10i + 3i + 15i^2 = 2 + 13i - 15 = -13 + 13i.

  5. 5
    Divide each part by 26

    (-13 + 13i) / 26 = -13/26 + (13/26)i = -1/2 + (1/2)i.

Result

-1/2 + (1/2)i

Functions That Accept Complex Inputs

Beyond the four arithmetic operations, the most common mathematical functions are also supported for complex numbers. This means that a complex value can be passed into a function, and the function's result is again interpreted as a complex quantity. The idea is the same as for arithmetic: the complex number is a legitimate input, not a special case that must be avoided.

The source introduces this support briefly and does not list the individual functions. The key point to take away is the general support rather than a particular catalogue of functions. When you meet a specific function, the question to ask is whether it accepts complex arguments and returns a complex result, and the general statement above tells you that the common functions do.

Mistakes When Computing With Complex Values

Most errors with complex numbers come from handling the parts incorrectly rather than from the operations themselves. The table below contrasts the correct handling of each step with the common error, so you can check your own work against it.

Keep i as a symboli is not an ordinary realTreat i as anordinary realcombining i with real termsReplace i^2 with -1during multiplicationLeave i^2 in theanswerinstead of -1Combine real partsseparatelyfrom imaginary partsMix real andimaginary partsin one totalUse the conjugate ofthe denominatorto divideMultiply denominatorby c+diinstead of its conjugate
Side-by-side contrast of the correct treatment of i and of the parts against the typical mistakes learners make.
  • Common mistake

    Forgetting that i2 = -1 during multiplication

    What it looks like

    (2+3i)(1-5i) computed as 2 - 7i + 3i^2 instead of the correct 17 - 7i

    Why it fails

    The term 3i times -5i produces -15i^2, which is a real number, not an imaginary one. Leaving it as i2 or dropping it changes the real part.

    Do this instead

    Replace every i^2 with -1 before collecting terms, and check the sign of the bd i^2 term.

  • Common mistake

    Treating i as an ordinary real number

    Why it fails

    Combining i with real terms as if it were a plain number ignores the rule i2 = -1 and breaks the real-part and imaginary-part structure.

    Do this instead

    Keep the real parts and the imaginary parts separate, and only simplify i^2 using the rule i^2 = -1.

  • Common mistake

    Multiplying by the denominator instead of its conjugate when dividing

    What it looks like

    Multiplying (2+3i)/(1-5i) top and bottom by 1-5i

    Why it fails

    The denominator stays complex, so the imaginary unit is not removed from it.

    Do this instead

    Multiply top and bottom by the conjugate, 1+5i, so the denominator becomes the real number 26.

  • Common mistake

    Combining real and imaginary parts in one total

    Why it fails

    Addition and subtraction work by combining real parts with real parts and imaginary parts with imaginary parts. Merging them into a single number loses the structure.

    Do this instead

    Write the answer as one real number plus one imaginary part, such as 2 - 5i.

Practice Tracing the Parts

MEDIUM

Compute (4+2i) + (1-6i), then compute (4+2i)(1-6i) by expanding and replacing i2 with -1. Write each answer in the form real part plus imaginary part i, and check the sign of the i2 term in the product.

Hints
  • For the sum, add the real parts 4 and 1, then add the imaginary parts 2 and -6.
  • For the product, the four terms are 4, -24i, 2i and -12i^2. Replace i2 with -1 in the last term before collecting.

Summary of Complex Arithmetic

  1. 1
    Complex numbers have the form a + bi, with real part a and imaginary part b, and support the usual arithmetic operations.
  2. 2
    Addition and subtraction combine real parts with real parts and imaginary parts with imaginary parts.
  3. 3
    Multiplication expands the product and uses i2 = -1, and division multiplies top and bottom by the conjugate of the denominator.
  4. 4
    Common mathematical functions are also supported for complex numbers, so a complex value can be passed into them and the result is again a complex quantity.

At a glance

  • Complex numbers have the form a + bi, with real part a and imaginary part b, and they support the usual arithmetic operations.
  • Addition and subtraction combine real parts with real parts and imaginary parts with imaginary parts.
  • Multiplication expands the product and uses i2 = -1, while division multiplies top and bottom by the conjugate of the denominator.
  • Common mathematical functions also accept complex inputs, and their results are again complex quantities.

Related concepts

More concepts starting with C